Aleksandrów (Legionowo Kūn)
Aleksandrów sī chi̍t ê tī Pho-lân Kiōng-hô-kok Masovia Séng Legionowo Kūn Nieporęt Kong-siā ê chng-thâu.[1]
| Aleksandrów | |
| — Chng-thâu — | |
  Aleksandrów |
|
| Keng-hūi-tō͘: 52°23′48″N 21°2′41″E / 52.39667°N 21.04472°E | |
| Kok-ka |  Pho-lân
|
|---|---|
| Séng | Masovia |
| Kūn | Legionowo |
| Kong-siā | Nieporęt |
| Sî-khu | CET (UTC+1) |
| - Jo̍at--lâng | CEST (UTC+2) |
Chham-oa̍t
siu-káiChham-khó
siu-kái- ↑ "Central Statistical Office (GUS) - TERYT (National Register of Territorial Land Apportionment Journal)" (ēng Pho-lân-gí). 2008-06-01.