Aleksandrowo (Sejny Kūn)

Aleksandrowo sī chi̍t ê tī Pho-lân Kiōng-hô-kok Podlaskie Séng Sejny Kūn Krasnopol Kong-siā ê chng-thâu.[1]

Aleksandrowo
—  Chng-thâu  —
Aleksandrowo is located in Pho-lân
Aleksandrowo
Aleksandrowo
Keng-hūi-tō͘: 54°5′47″N 23°9′29″E / 54.09639°N 23.15806°E / 54.09639; 23.15806
Kok-ka  Pho-lân
Séng Podlaskie
Kūn Sejny
Kong-siā Krasnopol
Sî-khu CET (UTC+1)
 - Jo̍at--lâng CEST (UTC+2)

Chham-oa̍t

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Chham-khó

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