"Thomas Barclay" pán-pún chi-kan bô-kāng--ê tē-hng

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[[Image:Thomas Barclay.jpg|thumb|right|200px|Pa-khek-lé Bok-sū]]'''Thomas Barclay''' ([[Hàn-jī]]: 巴克禮; [[POJ]]: '''Pa-khek-lé''')
'''Thomas Barclay''' ({{bd|1849 nî|11 goe̍h 21 ji̍t|1935 nî|10 goe̍h 5 ji̍t|B}}) sī [[Eng-kok]] [[So͘-keh-lân]] [[Glasgow]] chhut-sin ê [[Tiúⁿ-ló Kàu-hōe]] [[thoân-káu-sū]] kiam [[gí-giân-ha̍k]] ha̍k-chiá. Barclay ê [[Hàn-miâ]] hō-chò '''Pa-khek-lé''' (巴克禮). [[1875 nî]] 6-goe̍h chhe-5, 26-hòe ê Barclay tí-ta̍t [[Tâi-oân]] [[Táⁿ-káu]]; āu-lâi i tī [[Tâi-lâm]] siat-li̍p [[Tâi-lâm Sîn-ha̍k-īⁿ]], khai-sí tī [[Tâi-lâm]] chiông-sū thoân-kàu ê khang-khòe. 1935-nî 10-goe̍h chhe-5, Barclay tī Tâi-lâm kòe-sin, i kā in it-seng chòe-āu ê 60-nî lóng hōng-hiàn hō͘ Tâi-oân.
 
==Chá-nî==
Barclay tī 1849 nî 11 goe̍h 21 ji̍t ê So͘-keh-lân [[Glasgow]] chhut-sì. I sī chhù-lāi 5-ê hiaⁿ-tī lāi siāng sè-hàn--ê; i lēng-gōa iáu-ū 1-ê sió-mōe. Barclay ê chó͘-sian lâi-chū [[Hoat-lân-se]].
 
==Tù-chok==