Lambertschaag
Lambertschaag sī Hô-lân Pak-Holland séng Medemblik chū-tī-thé lāi-bīn ê chi̍t ê chng-thâu.
Lambertschaag | |||
— Chng-thâu — | |||
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Lambertschaag tī Hô-lân ê iok-lio̍k ūi-tì | |||
Keng-hūi-tō͘: 52°44′45″N 5°1′0″E / 52.74583°N 5.01667°E | |||
Kok-ka | Hô-lân | ||
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Séng | Pak-Holland | ||
Chū-tī-thé | Medemblik |