"Chū-jiân-sò͘" pán-pún chi-kan bô-kāng--ê tē-hng
刪去的內容 新增的內容
~無編輯摘要 |
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Tē 29 chōa:
Kú 1-ê te̍k-piat ê lē. ''a'' × 1 = ''a'' ×''S''(0) = ''a''. Só͘-í 1 sī chū-jiân-sò͘ ê seng-hoat tan-ūi-goân. ('''N''', ×) mā chiâⁿ-sêng 1-ê ū tan-ūi-goân ê poàⁿ-kûn.
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