Aleksandrów (Żychlin Kong-siā)
Aleksandrów sī chi̍t ê tī Pho-lân Kiōng-hô-kok Łódź Séng Kutno Kūn Żychlin Kong-siā ê chng-thâu.[1]
Aleksandrów | |
— Chng-thâu — | |
Keng-hūi-tō͘: 52°14′22″N 19°33′58″E / 52.23944°N 19.56611°E | |
Kok-ka | Pho-lân |
---|---|
Séng | Łódź |
Kūn | Kutno |
Kong-siā | Żychlin |
Sî-khu | CET (UTC+1) |
- Jo̍at--lâng | CEST (UTC+2) |
Chham-oa̍t
siu-káiChham-khó
siu-kái- ↑ "Central Statistical Office (GUS) - TERYT (National Register of Territorial Land Apportionment Journal)" (ēng Pho-lân-gí). 2008-06-01.