Aleksandrów (Koło Kūn)
Aleksandrów sī chi̍t ê tī Pho-lân Kiōng-hô-kok Tōa Pho-lân Séng Koło Kūn Chodów Kong-siā ê chng-thâu.[1]
| Aleksandrów | |
| — Chng-thâu — | |
  Aleksandrów |
|
| Keng-hūi-tō͘: 52°15′N 18°59′E / 52.250°N 18.983°E | |
| Kok-ka |  Pho-lân
|
|---|---|
| Séng | Tōa Pho-lân |
| Kūn | Koło |
| Kong-siā | Chodów |
| Sî-khu | CET (UTC+1) |
| - Jo̍at--lâng | CEST (UTC+2) |
Chham-oa̍t siu-kái
Chham-khó siu-kái
- ↑ "Central Statistical Office (GUS) - TERYT (National Register of Territorial Land Apportionment Journal)" (ēng Pho-lân-gí). 2008-06-01.