Aleksandrówka (Lubartów Kūn)
Aleksandrówka sī chi̍t ê tī Pho-lân Kiōng-hô-kok Lublin Séng Lubartów Kūn Michów Kong-siā ê chng-thâu.[1]
Aleksandrówka | |
— Chng-thâu — | |
Keng-hūi-tō͘: 51°29′N 22°24′E / 51.483°N 22.400°E | |
Kok-ka | Pho-lân |
---|---|
Séng | Lublin Séng |
Kūn | Lubartów Kūn |
Kong-siā | Michów Kong-siā |
Sî-khu | CET (UTC+1) |
- Jo̍at--lâng | CEST (UTC+2) |
Chham-oa̍t
siu-káiChham-khó
siu-kái- ↑ "Central Statistical Office (GUS) - TERYT (National Register of Territorial Land Apportionment Journal)" (ēng Pho-lân-gí). 2008-06-01.