Aleksandrowo (Żnin Kūn)
Aleksandrowo sī chi̍t ê tī Pho-lân Kiōng-hô-kok Kuyavia-Pomerania Séng Żnin Kūn Barcin Kong-siā ê chng-thâu.[1]
| Aleksandrowo | |
| — Chng-thâu — | |
  Aleksandrowo |
|
| Keng-hūi-tō͘: 52°48′53″N 18°2′58″E / 52.81472°N 18.04944°E | |
| Kok-ka |  Pho-lân
|
|---|---|
| Séng | Kuyavia-Pomerania |
| Kūn | Żnin |
| Kong-siā | Barcin |
| Sî-khu | CET (UTC+1) |
| - Jo̍at--lâng | CEST (UTC+2) |
Chham-oa̍t siu-kái
Chham-khó siu-kái
- ↑ "Central Statistical Office (GUS) - TERYT (National Register of Territorial Land Apportionment Journal)" (ēng Pho-lân-gí). 2008-06-01.