Aleksandrowo (Siemiatycze Kūn)
Aleksandrowo sī chi̍t ê tī Pho-lân Kiōng-hô-kok Podlaskie Séng Siemiatycze Kūn Grodzisk Kong-siā ê chng-thâu.[1]
| Aleksandrowo | |
| — Chng-thâu — | |
  Aleksandrowo |
|
| Keng-hūi-tō͘: 52°34′N 22°48′E / 52.567°N 22.800°E | |
| Kok-ka |  Pho-lân
|
|---|---|
| Séng | Podlaskie |
| Kūn | Siemiatycze |
| Kong-siā | Grodzisk |
| Sî-khu | CET (UTC+1) |
| - Jo̍at--lâng | CEST (UTC+2) |
Chham-oa̍t
siu-káiChham-khó
siu-kái- ↑ "Central Statistical Office (GUS) - TERYT (National Register of Territorial Land Apportionment Journal)" (ēng Pho-lân-gí). 2008-06-01.