Aleksandrowo (Siemiatycze Kūn)

Aleksandrowo sī chi̍t ê tī Pho-lân Kiōng-hô-kok Podlaskie Séng Siemiatycze Kūn Grodzisk Kong-siā ê chng-thâu.[1]

Aleksandrowo
—  Chng-thâu  —
Aleksandrowo is located in Pho-lân
Aleksandrowo
Aleksandrowo
Keng-hūi-tō͘: 52°34′N 22°48′E / 52.567°N 22.800°E / 52.567; 22.800
Kok-ka  Pho-lân
Séng Podlaskie
Kūn Siemiatycze
Kong-siā Grodzisk
Sî-khu CET (UTC+1)
 - Joa̍h-tang CEST (UTC+2)

Chham-oa̍t

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Chham-khó

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