Helenów (Węgrów Kūn)
Helenów sī chi̍t ê tī Pho-lân Kiōng-hô-kok Masovia Séng Węgrów Kūn Wierzbno Kong-siā ê chng-thâu.[1]
| Helenów | |
| — Chng-thâu — | |
  Helenów |
|
| Keng-hūi-tō͘: 52°17′28″N 21°51′20″E / 52.29111°N 21.85556°E | |
| Kok-ka |  Pho-lân
|
|---|---|
| Séng | Masovia |
| Kūn | Węgrów |
| Kong-siā | Wierzbno |
| Sî-khu | CET (UTC+1) |
| - Jo̍at--lâng | CEST (UTC+2) |
Chham-oa̍t siu-kái
Chham-khó siu-kái
- ↑ "Central Statistical Office (GUS) - TERYT (National Register of Territorial Land Apportionment Journal)" (ēng Pho-lân-gí). 2008-06-01.