Popowo (Szamotuły Kūn)
Popowo sī chi̍t ê tī Pho-lân Kiōng-hô-kok Tōa Pho-lân Séng Szamotuły Kūn Wronki Kong-siā ê chng-thâu.[1]
| Popowo | |
| — Chng-thâu — | |
  Popowo |
|
| Keng-hūi-tō͘: 52°42′57″N 16°19′6″E / 52.71583°N 16.31833°E | |
| Kok-ka |  Pho-lân
|
|---|---|
| Séng | Tōa Pho-lân |
| Kūn | Szamotuły |
| Kong-siā | Wronki |
| Sî-khu | CET (UTC+1) |
| - Jo̍at--lâng | CEST (UTC+2) |
Chham-oa̍t
siu-káiChham-khó
siu-kái- ↑ "Central Statistical Office (GUS) - TERYT (National Register of Territorial Land Apportionment Journal)" (ēng Pho-lân-gí). 2008-06-01.